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# Calendar – Aptitude MCQ Questions and Solutions with Explanations 2

11. The calendar for the year 2007 will be the same for the year:

Solution:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

 Year Odd Day 2007 1 2008 2 2009 1 2010 1 2011 1 2012 2 2013 1 2014 1 2015 1 2016 2 2017 1

Sum = 14 odd days ≡ 0 odd days.
∴ Calendar for the year 2018 will be the same as for the year 2007.

12. Which of the following is not a leap year?

Solution:

The century divisible by 400 is a leap year.
∴ The year 700 is not a leap year.

13. On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

Solution:

The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday.
∴ 8th Dec, 2006 is Friday.

14. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

Solution:

The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.

15. January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

Solution:

The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.

16. It was Thursday on 12th January 2006. What day of the week it will be on January 12th 2007 ?

Solution:

There is exactly 1 year, (365 days) between two dates.
2006 is an ordinary year. It has one odd day.
The day of the week on January 12th 2007 is one day beyond Thursday ⇒ Friday

17. What day of the week will 22 Apr 2222 be?

Solution:

22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2200
= Number of odd days in 200 years
= 5 x 2 = 10 = 3
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
Number of odd days in the period 2201-2221
= 16 normal years + 5 leap years
= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days
Number of days from 1-Jan-2222 to 22 Apr 2222
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112
112 days = 0 odd day
Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day
1 odd days = Monday
Hence 22 Apr 2222 is Monday

18. If today is Monday, what will be the day 350 days from now?

Solution:

350 days,

350/7

= 50, no odd days, so it will be a Monday.

19. What was the day of the week on 24th July 2011?

Solution:

Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7

=24+0+11+2+6/7=43/7=1=Sunday
20. If the first day of a year (other than leap year) was Friday, then which was the last day of that year?