Calendar – Aptitude MCQ Questions and Solutions with Explanations 3

Calendar – Aptitude MCQ Questions and Solutions with Explanations 3

21. What was the day of the week on 10th March 1996?

Answer: Option D
Solution:
10+4+96+24+0/7=134/7=1=Sunday
22. What day of the week was 20th June 1837?

Answer: Option B
Solution:

20th June, 1837 means 1836 complete years + first 5 months of the year 1837 + 20 days of June
1600 years give no odd days
200 years give 3 odd days
36 years give (36 + 9 ) or 3 odd days
Thus 1836 years give 6 odd days
From 1st January to 20th June there are 3 odd days
Odd days: January 3, February 0, March 3, April 2, May 3, June 6 = 17
Thus the total number of odd days = 6 + 3 or 2 odd days
This means that the 20th of June fell on 2nd day commencing from Monday.
The required day was Tuesday.

23. How many days will there be from 26th January, 1996 to 15th May, 1996 (both days included)?

Answer: Option B
Solution:

Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May)
= 111

24. Today is Thursday. What will be the day of the week after 94 days?

Answer: Option A
Solution:

94 days = (13 × 7) + 3 = 3 odd days.
The required day is 3 days beyond Thursday i.e., Sunday

25. What was the day on 25th January, 1975?

Answer: Option B
Solution:

Counting the years 1600 + 300 + 74
In 1600 years, there are zero odd days
In 300 years, there is one odd day
In 74 years, there are 18 leap years and 56 normal years, so the odd days are:
18(2) + 56(1) = 36 + 56 = 92,
Which is 13 weeks and 1 odd day
In 25 days of January, 1975, there are 3 weeks and 4 odd days
Total odd days = 0 + 1 + 1 + 4
six odd days, so it was a Saturday.

26. Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?

Answer: Option D
Solution:

Clearly it can be understood from the question that 9 days ago was a Thursday
Number of odd days in 9 days = 2 (As 9 – 7 = 2, reduced perfect multiple of 7 from total days)
Hence today = (Thursday + 2 odd days) = Saturday

27. On 2007, What was the date of last Saturday in May month?

Answer: Option C
Solution:

Calendar – Aptitude MCQ Questions and Solutions with Explanations

28. If the seventh day of a month is three days earlier than Friday, What day will it be on the nineteenth day of the month?

Answer: Option A
Solution:

Given that seventh day of a month is three days earlier than Friday
⇒ Seventh day is Tuesday
⇒ 14th is Tuesday
⇒ 19th is Sunday

29. Today is 3rd November. The day of the week is Monday. This is a leap year. What will be the day of the week on this date after 3 years?

Answer: Option D
Solution:

This is a leap year. So, none of the next 3 years will be leap years. Each year will give one odd day so the day of the week will be 3 odd days beyond Monday i.e. it will be Thursday.

30. If 1st October is Sunday, then 1st November will be

Answer: Option C
Solution:

Given that 1st October is Sunday
Number of days in October = 31
31 days = 3 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Hence 1st November = (Sunday + 3 odd days) = Wednesday

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