We will show that the number of odd days between last day of February and last day of October is zero.
March   April   May   June   July   Aug.   Sept.   Oct.
31 + 30 + 31 + 30 + 31 + 31 + 30 + 31
= 241 days
= 35 weeks
= 0 odd day
Number of odd days during this period = 0.
Thus, 1^st March of an year will be the same day as 1^st November of that year. Hence, the result follows

We already know that the calendar after a leap year repeats again after 28 years.
Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.

We know that, After every 400 years, the same day occurs.
Thus, if 9^th August 2016 is Saturday, before 400 years
i.e., on 9^th August 1616 has to be Saturday.

Given that the month begins on a Friday and has 31 days
Sundays = 3^rd, 10^th, 17^th, 24^th, 31^st
⇒ Total Sundays = 5
Every second & fourth Saturday is holiday. 2^nd & 4^th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 – (5 + 2) = 24 days.

The year 1996 is a leap year. So, it has 2 odd days. But 17th March comes after 29th February.
So, the day on 17^th March, 1997 will be 1 day beyond the day on 17^th March,1996.
Here 17^th March, 1997 is Monday. So, 17^th March, 1996 is Sunday.

When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days).
So, 1200 has 366 days.