**Calendar – Aptitude MCQ Questions and Solutions with Explanations**

**1. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?**

**2.What was the day of the week on 28**

^{th}May, 2006?**3.What was the day of the week on 17**

^{th}June, 1998?## Answer & Solution

**Option C**

17^{th} June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) ≡ 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

Therefore 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

**4.What will be the day of the week 15**

^{th}August, 2010?## Answer & Solution

**Option A**

15^{th} August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days.

Jan. Feb. March April Mayb June July Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

∴ 227 days = (32 weeks + 3 days) ≡ 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.

Given day is Sunday.

**5.Today is Monday. After 61 days, it will be:**

**7. On what dates of April, 2001 did Wednesday fall?**

## Answer & Solution

**Option D**

We shall find the day on 1^{st} April, 2001.

1^{st} April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April

(31 + 28 + 31 + 1) = 91 days ≡ 0 odd days.

Total number of odd days = (0 + 0 + 0) = 0

On 1^{st} April, 2001 it was Sunday.

In April, 2001 Wednesday falls on 4^{th}, 11^{th}, 18^{th} and 25^{th}.

**8. How many days are there in x weeks x days?**

**9. The last day of a century cannot be**

**10. On 8**

^{th}Feb, 2005 it was Tuesday. What was the day of the week on 8^{th}Feb, 2004?